WebEmbed this widget ». Added Aug 1, 2010 by Hildur in Mathematics. Differential equation,general DE solver, 2nd order DE,1st order DE. Send feedback Visit Wolfram Alpha. Web13 jun. 2024 · A pair of linear equations which has x = 0, y = -5 as a solution is (a) x+y=0/2x-3y=10 (b) x+y=3/2x-y=5 (c) 2x+3y+5=0/3x+2y=0/x-4y=0 (d) x-4y=14/5x-y=13 Answer Question. The number of solutions of the pair of linear equations x +3y – 4 = 0 and 2x +6 y = 7 is (a) 0 (b) 1 (c) 2 (d) infinite Answer Question. A’s age is six times B’s age.
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Web23 okt. 2024 · If the graph of equation 2x+ky=10k, intersect x-axis at point (5,0).Find the value of K 1 See answer Advertisement abroodie Answer: K= 1 Step-by-step explanation: The line of AOB intersects the graph at the x-axis at point (5,0) (5,0)= (x,y) (x=5, y=0) Soooo... 2x+ky=10k 2 (5)+k*0=10k 10=10k k=10/10 k=1 Advertisement New questions … WebThey are a bunch of ways to graph linear equations. What we'll do in this video is the most basic way. Where we will just plot a bunch of values and then connect the dots. I think you'll see what I'm saying. So here I have an equation, a linear equation. I'll rewrite it just in case that was too small. y is equal to 2x plus 7. I want to graph ... the effects of the trail of tears
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Web16 sep. 2024 · For what value of k, will the equations, x + 2y + (11 – k) = 0 and 2x + ky + (10 + k) = 0 represent the coincident lines : (a) k = 12 (b) k = 4 (c) k = 36 (d) k = 2 Answer Question 11. An equation ax + by + c = 0 is a linear equation in 2 variables, where a, b, c are : (a) natural numbers (b) whole numbers (c) integers (d) real numbers Answer WebIf the point (-3, 1/2) lies on the graph of the equation 2x+ky=-11, then find the value of k. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Web2 aug. 2024 · Draw the graphs of following equations: 2x – y = 1; x + 2y = 13 Find the solution of the equations from the graph and shade the triangular region formed by the lines and the y-axis. (2013) Solution: By plotting the points and joining them, the lines intersect at A(3,5). ∴ x = 3, y = 5 Here ∆ABC is the required triangle. Question 35. the effects of the war on drugs