NettetCorrect option is B) I=∫x 3+xx 3−1dx. I=∫[1− (x 3+x)(x+1)]dx. =∫1dx−∫x(x 2+1)x+1 dx. Now, x(x 2+1)x+1 = xA+ x 2+1Bx+C ..... (1) ⇒x+1=A(x 2+1)+(Bx+C)x. A+B=0. A=1,B=−1,C=1. NettetSolution Verified by Toppr ∫x+1x 3dx =∫ x+1(x 3+1−1)dx =∫ x+1(x 3+1)dx−∫x+1dx =∫ x+1(x+1)(x 2+x+1)dx−∫x+1dx =∫(x 2+x+1)dx−∫x+1dx = 3x 3+ 2x 2+x−log∣x+1∣+c where c is the constant of integration. Solve any question of Integrals with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions ∫ x 2+1x 6−1dx Easy View solution >
Evaluate the Integral integral of (x^3)/3 with respect to x
Nettet4. aug. 2024 · I know how to find the integral of $x^a$ (I'm using $a$ as a constant) - it's just $\frac{x^{a+1}}{a+1}$. But, how do you figure out $\int a^x$ or variations of this … NettetFind the integral of ((x^2-x-2)^3)/(x^3-4x). Try NerdPal! Our new app on iOS and Android . Calculators Topics Solving Methods Step Reviewer Go Premium. ENG • ESP. Topics Login. Tap to take a pic of the problem. Find the integral ... did michael oher ever reunite with his family
Find the integral of y = f(x) = 3/sqrt(x) dx (3 divide by square root ...
Nettet30. mar. 2024 · Ex 7.10, 9 (MCQ) - Value of integral (x - x^3)^1/3 / x^4 Chapter 7 Class 12 Integrals Serial order wise Ex 7.10 Ex 7.10, 9 (MCQ) - Chapter 7 Class 12 Integrals (Term 2) Last updated at March 16, 2024 by Teachoo Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 minute class for ₹ 499 ₹ 299 Transcript Nettet∫x 3+xx 3−1dx is equal to A x−logx+log(x 2+1)−tan −1x+c B x−logx+ 21log(x 2+1)−tan −1x+c C x+logx+ 21log(x 2+1)+tan −1x+c D x+logx− 21log(x 2+1)−tan −1x+c Medium Solution Verified by Toppr Correct option is B) I=∫x 3+xx 3−1dx I=∫[1− (x 3+x)(x+1)]dx =∫1dx−∫x(x 2+1)x+1 dx Now, x(x 2+1)x+1 = xA+ x 2+1Bx+C ..... (1) ⇒x+1=A(x … NettetLet I = ∫ x3+xx3−1dx = ∫ (1− x3+xx+1)dx = ∫ 1dx −∫ x(x2+1)x+1 dx = x−∫ x(x2+1)x+1 .... (i) Now x(x2+1)x+1 = xA + x2+1Bx+C (By using partial fractions) ⇒ x +1 = A(x2 +1)+(Bx +C)x ⇒ x +1 = (A+B)x2 +C x +A Comparing coefficients of x2,x and constant, we get A+B = 0,C = 1,A = 1 ⇒ B = −1 ∴ From (i), we get I = x− ∫ x1dx −∫ x2+11−x dx did michael oher ever marry