WebNov 29, 2016 · acc;累加器a的内容压栈保存,(sp)=(sp)+1 pop b;堆栈内保存的累加器a的内容弹出到b寄存器中,(sp)=(sp)-1 使用push、pop指令使用堆栈,要注意进出栈的匹配,否则将引起不可预期的后果。 另外 如果把30h赋给了sp,称为设置栈底。以 … WebJan 3, 2011 · It's only useful to push imm/pop reg for small values that fit in an 8-bit immediate. Like push 1 (2 bytes) / pop eax (1 byte) for 3 bytes total, vs. mov eax, 1 (5 bytes total, with 3 zero bytes in the imm32 so it's also a problem for shellcode). See Tips for golfing in x86/x64 machine code.Also, swapping registers that way is insane vs. xchg eax, …
51单片机堆栈操作指令举例说明 - 21ic电子网
WebApr 8, 2024 · Something like this (have not tested beyond the fact that it assembles): mov B, R0 mov R0, #0 loop: mov A, @R0 push ACC inc R0 cjne R0, #20h, loop ; figure out which … WebFeb 22, 2015 · PUSH是压栈命令,POP是出栈命令 栈是一种先进后出的数据结构。 当执行push acc时,会根据sp寄存器的值,将数据存入RAM,然后对SP执行加1操作。 inex properties
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WebOnly the above case as you push values onto the stack - i.e. if you push a 16-bit at an even address followed by a 32-bit at an odd address. For an interrupt care is taken by the … WebJan 25, 2016 · push acc ;sp = sp + 1 = 51h, (51h)=30h mov a, b inc a ;a = 05h movc a, @a + dptr ;取出第5个字节50h push acc ;sp = sp + 1 = 52h, (52h)=50h ret ; 子程序返回指令. 执行 ret 指令时,是从堆栈中弹出两个字节到 pc 的高、低八 ... WebThe video explains the PUSH and POP opcodes of 8051 with the help of a small code which swaps the contents of two registers. inexpugnably